#299 (div.2) A. Tavas and Nafas

标签：简单模拟

1.题目描述：点击打开链接

2.解题思路：本题是一道简单的模拟题，要求将小于100的每个数的英文单词输出，提前打表即可。注意0，11~19要特殊处理。

3.代码：

#define _CRT_SECURE_NO_WARNINGS 
#include<iostream>
#include<algorithm>
#include<string>
#include<sstream>
#include<set>
#include<vector>
#include<stack>
#include<map>
#include<queue>
#include<deque>
#include<cstdlib>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<ctime>
#include<functional>
using namespace std;

#define INF 100000000
#define For(i,n) for(int i=0;i<(n);i++)
typedef long long ll;
char*s[] = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
char*t[] = {0, "ten", "twenty", "thirty","forty", "fifty", "sixty", "seventy", "eighty", "ninety" };
char*sp[] = { 0,"eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };

int main()
{
	//freopen("t.txt", "r", stdin);
	int n;
	while (~scanf("%d", &n))
	{
		int d = 0;
		int x = n;
		while (x > 0){ d++; x /= 10; }
		if (n < 10)
		{
			cout << s[n] << endl;
		}
		else if (n>10&&n < 20){
			cout << sp[n - 10] << endl;
		}
		else if (d == 2 && n % 10 == 0){
			cout << t[n / 10] << endl;
		}
		else if (n>=20&&d == 2 && (n % 10 != 0))
		{
			int x1 = n / 10, x2 = n % 10;
			cout << t[x1]<< '-' << s[x2] << endl;
		}
	}
	return 0;
}

#299 (div.2) A. Tavas and Nafas

标签：简单模拟

原文地址：http://blog.csdn.net/u014800748/article/details/45057727