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Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 5342 | Accepted: 3184 |
Description
1 5 3 2 5 1 3 4 4 2 5 1 2 3
Input
Output
Sample Input
14 5 1 5 3 2 5 1 3 4 4 2 5 1 2 3
Sample Output
3
Hint
Source
#include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<algorithm> #include<cstdlib> using namespace std; int n,k; bool vis[10010]; int main() { int ans=0,cnt=0,x; scanf("%d%d",&n,&k); for(int i=1;i<=n;i++) { scanf("%d",&x); if(!vis[x]) { vis[x]=1; cnt++; } if(cnt==k) { memset(vis,0,sizeof(vis)); cnt=0; ans++; } } printf("%d\n",ans+1); return 0; }
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原文地址:http://www.cnblogs.com/a972290869/p/4430180.html