标签:leetcode
Find Minimum in Rotated Sorted Array II Total Accepted: 23090 Total Submissions: 73108 My Submissions Question Solution
Follow up for “Find Minimum in Rotated Sorted Array”:
What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
The array may contain duplicates.
退化了。
class Solution {
public:
int findMin(vector<int>& nums) {
int size=nums.size();
int MIN=nums[0];
for(int i=1;i<size;++i)
if(nums[i]<MIN)MIN=nums[i];
return MIN;
}
};
188 / 188 test cases passed.
Status: Accepted
Runtime: 12 ms
LeetCode Find Minimum in Rotated Sorted Array II
标签:leetcode
原文地址:http://blog.csdn.net/wdkirchhoff/article/details/45065285