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10101
相当于排列组合的插空法,题目说不能有11,和001,那么我们可以这样考虑_1_1_1......在空的地方填0,
具体见代码注释
#include<cstdio> #include<algorithm> #include<cmath> #include<bits/stdc++.h> using namespace std; template<class T>inline T read(T&x) { char c; while((c=getchar())<=32)if(c==EOF)return 0; bool ok=false; if(c=='-')ok=true,c=getchar(); for(x=0; c>32; c=getchar()) x=x*10+c-'0'; if(ok)x=-x; return 1; } template<class T> inline T read_(T&x,T&y) { return read(x)&&read(y); } template<class T> inline T read__(T&x,T&y,T&z) { return read(x)&&read(y)&&read(z); } template<class T> inline void write(T x) { if(x<0)putchar('-'),x=-x; if(x<10)putchar(x+'0'); else write(x/10),putchar(x%10+'0'); } template<class T>inline void writeln(T x) { write(x); putchar('\n'); } //-------ZCC IO template------ const int maxn=1000001; const double inf=999999999; #define lson (rt<<1),L,M #define rson (rt<<1|1),M+1,R #define M ((L+R)>>1) #define For(i,t,n) for(int i=(t);i<(n);i++) typedef long long LL; typedef double DB; typedef pair<int,int> P; #define bug printf("---\n"); #define mod 1000000007 int main() { //#ifndef ONLINE_JUDGE //freopen("in.txt","r",stdin); //freopen("zccccc.txt","w",stdout); //#endif // ONLINE_JUDGE int n,m,i,j,t,k; while(read_(n,m)) { if(m-n>=2||(n==0&&m==0))//1比0个数多于2个以上,那么无论怎么放0,肯定有11在一起, puts("NO"); else if(m-n==1)//1比0 多一个,只能在1之间放0 { For(i,0,(n+m)/2) printf("10"); printf("1\n"); } else if(n-m==1)//0比1多一个,在0之间放1 { For(i,0,(n+m)/2) printf("01"); printf("0\n"); } else if(n==m)//相等就是01的循环 { For(i,0,n) printf("01"); printf("\n"); } else//0比1多余1个,那么要避免001,就得把01尽可能的放在前面 { For(i,0,m) printf("01"); For(i,0,n-m) printf("0"); printf("\n"); } } return 0; }
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原文地址:http://blog.csdn.net/u013167299/article/details/45077523