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2015.4.17 06:30
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.
For example, given the range [5, 7], you should return 4.
Solution:
Make it fast and simple.
Accepted code:
1 // 1AC, easy 2 class Solution { 3 public: 4 int rangeBitwiseAnd(int m, int n) { 5 while (n > m) { 6 n = (n & n - 1); 7 } 8 return m & n; 9 } 10 };
LeetCode - Bitwise AND of Numbers Range
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原文地址：http://www.cnblogs.com/zhuli19901106/p/4433865.html
