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题目:
Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2]
,
The longest consecutive elements sequence is [1, 2, 3, 4]
. Return its length: 4
.
Your algorithm should run in O(n) complexity.
代码:
class Solution { public: int longestConsecutive(vector<int> &num) { // hashmap record if element in num is visited std::map<int,bool> visited; for(std::vector<int>::iterator i = num.begin(); i != num.end(); ++i) { visited[*i] = false; } // search the longest consecutive unsigned int longest_global = 0; for(std::vector<int>::iterator i = num.begin(); i != num.end(); ++i) { if(visited[*i]) continue; unsigned int longest_local = 0; for(int j = *i+1; visited.find(j) != visited.end(); ++j) { visited[j] = true; ++longest_local; } for(int j = *i-1; visited.find(j) != visited.end(); --j) { visited[j] = true; ++longest_local; } longest_global = std::max(longest_global, longest_local+1); } return longest_global; } };
Tips:
1. 要想O(n), 而且无序,只能结合hashmap
2. 这里需要明确的一个逻辑是,通过hashmap前后访问,可以把包含当前元素的最大连同序列都找出来;而且访问过的元素不用再访问。
【Longest Consecutive Sequence】cpp
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原文地址:http://www.cnblogs.com/xbf9xbf/p/4436279.html