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Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
进行比较，遇到重复的跳过。
代码如下所示：
1 class Solution { 2 public: 3 ListNode *deleteDuplicates(ListNode *head) { 4 if(head == NULL || head->next == NULL) 5 return head; 6 ListNode *p; 7 ListNode *q; 8 q=head; 9 p=head->next; 10 while(p!=NULL) 11 { 12 if(p->val==q->val) 13 { 14 q->next=p->next; 15 p=q->next; 16 }else{ 17 p=p->next; 18 q=q->next; 19 } 20 } 21 return head; 22 } 23 };
【leetcode】Remove Duplicates from Sorted List
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原文地址：http://www.cnblogs.com/jawiezhu/p/4439639.html
