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LeetCode198——House Robber

时间:2015-04-21 00:28:04      阅读:154      评论:0      收藏:0      [点我收藏+]

标签:leetcode

这题告诉我们,要成为一个优秀的小偷,得懂编程才行。哈哈

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

Credits: Special thanks to @ifanchu for adding this problem and creating all test cases. Also thanks to @ts for adding additional test cases.

实现

int rob(vector<int> &num) {
    int prevF = 0, prevG = 0, f = 0, g = 0;
    for(int i=num.size()-1; i>=0; i--) {
        f = num[i] + prevG;
        g = max(prevF, prevG);
        prevF = f;
        prevG = g;
    }
    return max(f,g);
}

LeetCode198——House Robber

标签:leetcode

原文地址:http://blog.csdn.net/booirror/article/details/45157697

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