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Node* findMid(Node* &head){ if(head == NULL||head->next == NULL) return
head; Node* p = head; Node* q = head; while(q->next->next&&(q = q->next)) { p = p-> next; q = q->next; } return
p;} |
求单链表的中间节点，用快慢指针,布布扣,bubuko.com
原文地址：http://www.cnblogs.com/cliviazhou/p/3777624.html
