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题目来自于leetcode
https://leetcode.com/problems/path-sum/
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:sum
= 22
,
5 / 4 8 / / 11 13 4 / \ 7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2
which sum is 22.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void psum(TreeNode *root, int sum) { if(root!=NULL) { if(root->val==sum&&root->left==NULL&&root->right==NULL) { flag=true; return ; } psum(root->left, sum-root->val); psum(root->right, sum-root->val); //return false; } } bool hasPathSum(TreeNode *root, int sum) { if(root==NULL) return false; psum(root, sum) ; return flag; } bool flag=false; };
Path Sum Total Accepted: 50216 Total Submissions: 168425
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原文地址:http://blog.csdn.net/zhouyelihua/article/details/45173373