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做这个问题时没有看认真看题,把sorted看漏了,结果写了如下代码:虽然错了,但我觉得我下面这个代码写的还是挺不错的。
1 #include<iostream> 2 3 using namespace std; 4 5 int removeDuplicates(int A[], int n) { 6 int t = 0; 7 for (int i = 0; i < n; i++){ 8 A[i - t] = A[i]; 9 for (int j = 0; j < i-t; j++){ 10 if (A[i] == A[j]){ 11 t++; 12 break; 13 } 14 } 15 } 16 return n - t; 17 } 18 19 int main(){ 20 int A[] = {2, 2, 3, 4, 2, 5, 6, 3}; 21 int n = removeDuplicates(A, 8); 22 for (int i = 0; i < n; i++){ 23 cout << A[i] << endl; 24 } 25 cout << "n = " << n << endl; 26 }
改正后:
#include<iostream> using namespace std; int removeDuplicates(int A[], int n) { int t = 0; for (int i = 1; i < n; i++){ A[i - t] = A[i]; if (A[i-t] == A[i - t-1]){ t++; } } return n - t; } int main(){ int A[] = {2, 2, 3, 4, 4,5, 6, 6}; int n = removeDuplicates(A, 8); for (int i = 0; i < n; i++){ cout << A[i] << endl; } cout << "n = " << n << endl; }
leetcode Remove Duplicates from Sorted Array
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原文地址:http://www.cnblogs.com/chaiwentao/p/4445088.html