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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 16616 Accepted Submission(s):
8137
#include<stdio.h>
int set[2100];
int find(int fa) //找到根节点
{
int ch=fa;
int t;
while(fa!=set[fa])
fa=set[fa];
while(ch!=fa)
{
t=set[ch];
set[ch]=fa;
ch=t;
}
return fa;
}
int mix(int x,int y) //合并已有人数
{
int fx,fy;
fx=find(x);
fy=find(y);
if(fx!=fy)
set[fx]=fy;
}
int main()
{
int n,m,j,i,table,people,s;
scanf("%d",&n);
while(n--)
{
scanf("%d %d",&people,&table);
for(i=1;i<=people;i++)
set[i]=i;
for(i=1;i<=table;i++)
{
scanf("%d %d",&m,&j);
mix(m,j);
}
s=0;
for(i=1;i<=people;i++)
{
if(set[i]==i)
s++; //需要的桌子数
}
printf("%d\n",s);
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4445559.html