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题目来自于：LeetCode
https://leetcode.com/problems/minimum-path-sum/
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
int minPathSum(int **grid, int nRows, int nCols) {
if(nRows==0)
return 0;
int sum=0;
if(nRows==1)
{
for(int i=0;i<nCols;++i)
sum+=grid[0][i];
return sum;
}
if(nCols==1)
{
for(int i=0;i<nRows;++i)
sum+=grid[i][0];
return sum;
}
for(int i=nRows-2;i>=0;--i)
grid[i][nCols-1]+=grid[i+1][nCols-1];
for(int j=nCols-2;j>=0;--j)
grid[nRows-1][j]+=grid[nRows-1][j+1];
for(int i=nRows-2;i>=0;--i)
for(int j=nCols-2;j>=0;--j)
{
if(grid[i+1][j]<grid[i][j+1])
grid[i][j]+=grid[i+1][j];
else
grid[i][j]+=grid[i][j+1];
}
return grid[0][0];
}Minimum Path Sum Total Accepted: 34975 Total Submissions: 109325
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原文地址：http://blog.csdn.net/zhouyelihua/article/details/45196867
