Assign the task
Time Limit: 1 Sec Memory Limit: 256 MB
题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=3974
Description
There is a company that has N employees(numbered from 1 to N),every employee in the company has a immediate boss (except for the leader of whole company).If you are the immediate boss of someone,that person is your subordinate, and all his subordinates are your subordinates as well. If you are nobody‘s boss, then you have no subordinates,the employee who has no immediate boss is the leader of whole company.So it means the N employees form a tree.
The company usually assigns
some tasks to some employees to finish.When a task is assigned to
someone,He/She will assigned it to all his/her subordinates.In other
words,the person and all his/her subordinates received a task in the
same time. Furthermore,whenever a employee received a task,he/she will
stop the current task(if he/she has) and start the new one.
Write
a program that will help in figuring out some employee’s current task
after the company assign some tasks to some employee.
Input
The first line contains a single positive integer T( T <= 10 ), indicates the number of test cases.
For each test case:
The first line contains an integer N (N ≤ 50,000) , which is the number of the employees.
The
following N - 1 lines each contain two integers u and v, which means
the employee v is the immediate boss of employee u(1<=u,v<=N).
The next line contains an integer M (M ≤ 50,000).
The following M lines each contain a message which is either
"C x" which means an inquiry for the current task of employee x
or
"T x y"which means the company assign task y to employee x.
(1<=x<=N,0<=y<=10^9)
For each test case, print the test case number (beginning with 1) in the first line and then for every inquiry, output the correspond answer per line.
//qscqesze
#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 200001
#define mod 10007
#define eps 1e-9
int Num;
char CH[20];
//const int inf=0x7fffffff; //нчоч╢С
const int inf=0x3f3f3f3f;
/*
inline void P(int x)
{
Num=0;if(!x){putchar(‘0‘);puts("");return;}
while(x>0)CH[++Num]=x%10,x/=10;
while(Num)putchar(CH[Num--]+48);
puts("");
}
*/
//**************************************************************************************
inline ll read()
{
int x=0,f=1;char ch=getchar();
while(ch<‘0‘||ch>‘9‘){if(ch==‘-‘)f=-1;ch=getchar();}
while(ch>=‘0‘&&ch<=‘9‘){x=x*10+ch-‘0‘;ch=getchar();}
return x*f;
}
inline void P(int x)
{
Num=0;if(!x){putchar(‘0‘);puts("");return;}
while(x>0)CH[++Num]=x%10,x/=10;
while(Num)putchar(CH[Num--]+48);
puts("");
}
struct node
{
int x,y;
}a[maxn];
int pa[maxn];
int main()
{
char s[10];
int b,c;
int t=read();
for(int cas=1;cas<=t;cas++)
{
int n=read();
memset(a,0,sizeof(a));
memset(pa,-1,sizeof(pa));
for(int i=0;i<n-1;i++)
{
int u=read(),v=read();
pa[u]=v;
}
for(int i=0;i<=n;i++)
{
a[i].x=-1;
a[i].y=-1;
}
int m=read();
printf("Case #%d:\n",cas);
int co=0;
for(int i=0;i<m;i++)
{
scanf("%s",s);
if(s[0]==‘C‘)
{
b=read();
int k=a[b].x;
int y=a[b].y;
while(b!=-1)
{
if(a[b].y>y)
{
k=a[b].x;
y=a[b].y;
}
b=pa[b];
}
printf("%d\n",k);
}
else
{
b=read(),c=read();
a[b].x=c;
a[b].y=++co;
}
}
}
}
