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leetcode_64_Minimum Path Sum

时间:2015-04-26 09:19:46      阅读:106      评论:0      收藏:0      [点我收藏+]

标签:c++   leetcode   dp   

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64 Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.


Note: You can only move either down or right at any point in time.




//方法一:dp,不优化空间
class Solution {
public:
    int minPathSum(vector<vector<int> > &grid) {
        int m = grid.size();
        int n = grid[0].size();
        vector<vector<int> > dp(m , vector<int>(n));
        for(int i=0; i<m; i++)
            for(int j=0; j<n; j++)
            {
                if(i==0)
                {
                    if(j==0)
                        dp[i][j] = grid[i][j];
                    else
                        dp[i][j] = dp[i][j-1] + grid[i][j];
                }
                else if(j==0)
                {
                    dp[i][j] = dp[i-1][j] + grid[i][j];
                }
                else
                    dp[i][j] = min(dp[i-1][j], dp[i][j-1]) + grid[i][j];
            }
            
        return dp[m-1][n-1];
    }
};

//方法二:dp,优化空间
class Solution {
public:
    int minPathSum(vector<vector<int> > &grid) {
        int m = grid.size();
        int n = grid[0].size();
        vector<int> dp(n);
        for(int i=0; i<m; i++)
            for(int j=0; j<n; j++)
            {
                if(i==0)
                {
                    if(j==0)
                        dp[j] = grid[i][j];
                    else
                        dp[j] = dp[j-1] + grid[i][j];
                }
                else if(j==0)
                {
                    dp[j] = dp[j] + grid[i][j];
                }
                else
                    dp[j] = min(dp[j], dp[j-1]) + grid[i][j];
            }
            
        return dp[n-1];
    }
};


leetcode_64_Minimum Path Sum

标签:c++   leetcode   dp   

原文地址:http://blog.csdn.net/keyyuanxin/article/details/45278861

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