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Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
判断一颗二叉树,各个节点的左右子树深度是否相同。
1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 int flag=true; 13 int dfs(TreeNode *root) 14 { 15 if(root==NULL) return true; 16 int h1,h2; 17 if(root->left==NULL) h1=0; 18 else h1=dfs(root->left); 19 if(root->right==NULL) h2=0; 20 else h2=dfs(root->right); 21 if(abs(h1-h2)>1) flag=0; 22 return max(h1,h2)+1; 23 } 24 bool isBalanced(TreeNode *root) { 25 dfs(root); 26 return flag; 27 } 28 };
定义一个函数dfs,递归调用,对左右子节点的子树深度进行判断。
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原文地址:http://www.cnblogs.com/zongmeng/p/4457899.html