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Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
两个已经排序的链表,按照升序组合为一个链表
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { 12 if(l1==NULL)return l2; 13 if(l2==NULL)return l1; 14 15 ListNode *ret = NULL; 16 17 if (l1->val < l2->val) 18 { 19 ret = l1; 20 ret->next = mergeTwoLists(l1->next, l2); 21 } 22 else 23 { 24 ret = l2; 25 ret->next = mergeTwoLists(l1, l2->next); 26 } 27 28 return ret; 29 } 30 };
leetcode:Merge Two Sorted Lists
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原文地址:http://www.cnblogs.com/zongmeng/p/4458068.html