码迷,mamicode.com
首页 > 其他好文 > 详细

leetcode--Count and Say

时间:2014-06-10 10:41:04      阅读:147      评论:0      收藏:0      [点我收藏+]

标签:c   class   blog   code   java   a   

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
public class Solution {
    /**It is simple problem.
     * @author Averill Zheng
     * @version 2014-06-07
     * @since JDK 1.7
     */
    public String countAndSay(int n) {
        String result = "1";
        for(int i = 1; i < n; ++i){
            StringBuffer resultBuffer = new StringBuffer();
            int length = result.length();
            char currentChar = result.charAt(0);
            int count = 0;
            for(int j = 0; j < length; ++j){
                if(currentChar != result.charAt(j)){
                    resultBuffer.append(count);
                    resultBuffer.append(currentChar - ‘0‘);
                    currentChar = result.charAt(j);
                    count = 1;
                }
                else
                    ++count;
            }
            resultBuffer.append(count);
            resultBuffer.append(currentChar - ‘0‘);
            result = resultBuffer.toString();
        }
        return result;
    }
}

  

leetcode--Count and Say,布布扣,bubuko.com

leetcode--Count and Say

标签:c   class   blog   code   java   a   

原文地址:http://www.cnblogs.com/averillzheng/p/3779165.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!