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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 16562 Accepted Submission(s): 7443
#include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<cstdlib> #include<algorithm> #include<queue> #include<vector> #include<stack> #include<set> using namespace std; int num[4],val[4]; int c1[8005],c2[8005],maxx; int main() { val[1]=1,val[2]=2,val[3]=5; while(scanf("%d%d%d",&num[1],&num[2],&num[3])!=EOF) { if(num[1]+num[2]+num[3]==0) break; maxx=num[1]+2*num[2]+5*num[3]; memset(c1,0,sizeof(c1)); memset(c2,0,sizeof(c2)); for(int i=0;i<=num[1];i++) c1[i]=1; for(int i=2;i<=3;i++) { for(int j=0;j<=maxx;j++) { if(c1[j]) { for(int k=0;k<=val[i]*num[i];k+=val[i]) { if(k+j<=maxx) c2[k+j]+=c1[j]; } } } for(int j=0;j<=maxx;j++) c1[j]=c2[j],c2[j]=0; } int i; for(i=1;i<=maxx;i++) { if(c1[i]==0) { printf("%d\n",i); break; } } if(i==maxx+1) printf("%d\n",maxx+1); } return 0; }
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原文地址:http://www.cnblogs.com/water-full/p/4461144.html