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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 16562 Accepted Submission(s): 7443

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<cstdlib>
#include<algorithm>
#include<queue>
#include<vector>
#include<stack>
#include<set>
using namespace std;
int num[4],val[4];
int c1[8005],c2[8005],maxx;
int main()
{
val[1]=1,val[2]=2,val[3]=5;
while(scanf("%d%d%d",&num[1],&num[2],&num[3])!=EOF)
{
if(num[1]+num[2]+num[3]==0)
break;
maxx=num[1]+2*num[2]+5*num[3];
memset(c1,0,sizeof(c1));
memset(c2,0,sizeof(c2));
for(int i=0;i<=num[1];i++)
c1[i]=1;
for(int i=2;i<=3;i++)
{
for(int j=0;j<=maxx;j++)
{
if(c1[j])
{
for(int k=0;k<=val[i]*num[i];k+=val[i])
{
if(k+j<=maxx)
c2[k+j]+=c1[j];
}
}
}
for(int j=0;j<=maxx;j++)
c1[j]=c2[j],c2[j]=0;
}
int i;
for(i=1;i<=maxx;i++)
{
if(c1[i]==0)
{
printf("%d\n",i);
break;
}
}
if(i==maxx+1)
printf("%d\n",maxx+1);
}
return 0;
}
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原文地址:http://www.cnblogs.com/water-full/p/4461144.html