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Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5822 Accepted Submission(s): 3469
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<cstdlib>
#include<algorithm>
#include<queue>
#include<vector>
using namespace std;
vector<int> e[205];
int n,m,dp[205][205],w[205];
void dfs(int x,int sum)
{
dp[x][1]=w[x];
for(int i=0;i<e[x].size();i++)
{
if(sum>1) dfs(e[x][i],sum-1);
for(int j=sum-1;j>=1;j--)
{
int v=j+1;
for(int k=1;k<v;k++)
{
dp[x][v]=max(dp[x][v],dp[x][v-k]+dp[e[x][i]][k]);
}
}
}
}
int main()
{
int x;
while(scanf("%d%d",&n,&m)!=EOF)
{
if(n+m==0)
break;
memset(dp,0,sizeof(dp));
for(int i=0;i<=n;i++)
e[i].clear();
for(int i=1;i<=n;i++)
{
scanf("%d%d",&x,&w[i]);
e[x].push_back(i);
}
dfs(0,m+1);
printf("%d\n",dp[0][m+1]);
}
return 0;
}
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原文地址:http://www.cnblogs.com/water-full/p/4461582.html