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Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
用哈希表记录下字符的映射,只要保证1对1映射就行
public class Solution {
public boolean isIsomorphic(String s, String t) {
Map<Character, Character> map1 = new HashMap<>();
Map<Character, Character> map2 = new HashMap<>();
for (int i = 0; i < s.length(); i++) {
char a = s.charAt(i);
char b = t.charAt(i);
if (map1.containsKey(a) && map1.get(a) != b) {
return false;
}
if (map2.containsKey(b) && map2.get(b) != a) {
return false;
}
map1.put(a, b);
map2.put(b, a);
}
return true;
}
}
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原文地址:http://www.cnblogs.com/shini/p/4465401.html