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2. Add Two Numbers

时间:2015-04-29 13:08:35      阅读:113      评论:0      收藏:0      [点我收藏+]

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You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

Cracking Interview 原题

/**
* Definition for singly-linked list.
* public class ListNode {
*    int val;
*    ListNode next;
*    ListNode(int x) {
*      val = x;
*      next = null;
*    }
* }
*/
public class Solution {
  public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
    ListNode result = new ListNode(0);
    ListNode tmp = result;
    int carry = 0;
    while(l1 != null && l2 != null) {
      int sum = l1.val + l2.val + carry;
      carry = sum / 10;
      tmp.next = new ListNode(sum % 10);
      tmp = tmp.next;
      l1 = l1.next;
      l2 = l2.next;
    }
    while(l1 != null) {
      int sum = l1.val + carry;
      carry = sum / 10;
      tmp.next = new ListNode(sum % 10);
      tmp = tmp.next;
      l1 = l1.next;
    }
    while(l2 != null) {
      int sum = l2.val + carry;
      carry = sum / 10;
      tmp.next = new ListNode(sum % 10);
      tmp = tmp.next;
      l2 = l2.next;
    }
    if (carry == 1) {
      tmp.next = new ListNode(carry);
    }
    return result.next;
  }
}

2. Add Two Numbers

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原文地址:http://www.cnblogs.com/shini/p/4465463.html

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