标签:leetcode
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
,
return true.
Given "foo"
, "bar"
,
return false.
Given "paper"
, "title"
,
return true.
Note:
You may assume both s and t have the same length.
class Solution { public: bool isIsomorphic(string s, string t) { int len1=s.length(); map<char,char> m; map<char,char> m2; for(int i=0;i<len1;i++){ if(m.find(s[i])==m.end()&&m2.find(t[i])==m2.end()){ m[s[i]]=t[i]; m2[t[i]]=s[i]; }else if(m[s[i]]!=t[i]||m2[t[i]]!=s[i]){ return false; } } return true; } };
标签:leetcode
原文地址:http://blog.csdn.net/u010786672/article/details/45399507