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LeetCode: Count and Say 题解

时间:2014-06-13 00:54:33      阅读:376      评论:0      收藏:0      [点我收藏+]

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The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

本题的难点在于理解题目的意思。

最好的理解就是给出 111221之后的一个sample: 312211

如何理解呢?  将111221 拆成后面的表达式即可: 111, 22, 1 其中有 3个one , 2个two, 1个one ,读起来就是: 312211

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 1 class Solution {
 2 public:
 3     string countAndSay(int n) {
 4         string a="1";
 5         if(n==1) return a;
 6         for(int i=2;i<=n;i++)
 7         {
 8             string b;
 9             char current = a[0];
10             int j=1,count=1;
11             for(j=1;j<a.size();j++)
12             {
13                 if(a[j]==current)
14                 {
15                     count++;
16                 }
17                 else
18                 {
19                     char c = count +0;
20                     b+=c;
21                     b+=current;
22                     current = a[j];
23                     count=1;
24                 }
25             }
26             char c = count+0;
27             b+=c;
28             b+=current;
29             a= b;
30         }
31         return a;
32     }
33 };
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转载请注明出处: http://www.cnblogs.com/double-win/ 谢谢

LeetCode: Count and Say 题解,布布扣,bubuko.com

LeetCode: Count and Say 题解

标签:style   class   blog   code   java   http   

原文地址:http://www.cnblogs.com/double-win/p/3781423.html

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