LeetCode Compare Version Numbers

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1.题目

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

2.解答

class Solution {
public:
    vector<string> getAllVersionString(string version1){
        vector<string> allVersion1;

        string oneVersion1;
        for(int i = 0; i < version1.size(); ++i){
            if(version1[i] != ‘.‘){
                oneVersion1.push_back(version1[i]);
            }else{
                allVersion1.push_back(oneVersion1);
                oneVersion1.clear();
            }
        }
        allVersion1.push_back(oneVersion1);
        return allVersion1;
    }
    int compareVer(vector<string> allVersion1, vector<string> allVersion2){
        for(int i = 0; i < allVersion1.size(); ++i){
               if(i < allVersion2.size()){
                   if(atoi(allVersion1[i].c_str()) < atoi(allVersion2[i].c_str())){
                       return -1;
                   }else if(atoi(allVersion1[i].c_str()) > atoi(allVersion2[i].c_str())){
                       return 1;
                   }
               }else{
                   if(atoi(allVersion1[i].c_str()) > 0){
                       return 1;
                   }
               }

        }
        return 0;
    }
    int compareVersion(string version1, string version2) {
        vector<string> allVersion1 = getAllVersionString(version1);
        vector<string> allVersion2 = getAllVersionString(version2);

        int result = 0;
        if(allVersion1.size() >= allVersion2.size()){
            result = compareVer(allVersion1, allVersion2);
        }else if(allVersion2.size() > allVersion1.size()){
            result = -compareVer(allVersion2, allVersion1);
        }
        return result;
    }
};

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LeetCode Compare Version Numbers

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原文地址：http://blog.csdn.net/fox64194167/article/details/45421715