POJ 1018 离散最优化枚举

标签：枚举

#include <cstdio>
#include <iostream>
#include <algorithm>
#include <queue>
#include <stack>
#include <cstdlib>
#include <cmath>
#include <set>
#include <map>
#include <vector>
#define INF 100000000
using namespace std;
struct node{
	int b,p;
	bool operator <(const node& a)const{
		if(b == a.b){
			return p < a.p;
		}
		else{
			return b < a.b;
		}
	}
	
};
node a[105][105];
int m[105];

int main(){
	int t;
	cin >> t;
	while(t--){
		int n;
		cin >> n;
		set<int> se;
		for(int i = 0;i < n;i++){
			scanf("%d",&m[i]);
			
			for(int j = 0;j < m[i];j++){
				scanf("%d%d",&a[i][j].b,&a[i][j].p);
				if(se.find(a[i][j].b) == se.end()){
					se.insert(a[i][j].b);
				}
				
			}	
			sort(a[i],a[i]+m[i]);
					
		}
		
		set<int>::iterator ite = se.begin();
		double ans = 0;
		for(ite = se.begin();ite != se.end();ite++){
			node  q;
			q.b = *ite;
			q.p = 0;
			int p = 0;
			int flag = 0;
			for(int i = 0;i < n;i++){
				int x = INF;
				
				for(int j = 0;j < m[i];j++){
					if(a[i][j].b >= q.b){
						if(a[i][j].p < x){
							x = a[i][j].p;
						}
					}
				}
				if(x == INF){
					flag = 1;
				}
				else{
					p += x;
				}
			}
			if(flag){
				break;
			}
			else{
				ans = max(ans,q.b*1.0/p); 
			}
		}
		printf("%.3lf\n",ans); 
	}
	return 0;
}

POJ 1018 离散最优化枚举

标签：枚举

原文地址：http://blog.csdn.net/qq_24667639/article/details/45486203