POJ 1125 Stockbroker Grapevine Floyd 最短路

标签：图   poj   

#include <cstdio>
#include <iostream>
#include <algorithm>
#include <queue>
#include <stack>
#include <cstdlib>
#include <cmath>
#include <set>
#include <map>
#include <vector>
#include <cstring>

#define INF 100000000
using namespace std;
int n;
int a[105][105];
int ans[105];

int main(){
	while(cin >> n,n){
		for(int i  = 1;i <= n;i++){
			for(int j = 1;j <= n;j++){
				a[i][j] = INF;
			}
		}
		int m;
		
		
		for(int i = 1;i <= n;i++){
			scanf("%d",&m);
			
			for(int j = 1;j <= m;j++){
				int x,v;
				scanf("%d%d",&x,&v);
				a[i][x] = v;
			}
		}
		
		for(int k = 1;k <= n;k++){
			for(int i = 1;i <= n;i++){
				for(int j = 1;j <= n;j++){
					a[i][j] = min(a[i][j],a[i][k]+a[k][j]); 
				}
			}
		} 
		int max = INF;
		int maxn;
		
		for(int i = 1;i <= n;i++){
			ans[i] = 0;
			
			for(int j = 1; j <= n;j++){
				if(i != j && a[i][j] > ans[i]){
					ans[i] = a[i][j];
					
				} 
			}
			if(ans[i] < max){
				max = ans[i];
				maxn = i;		
			}
		}
		if(max >= INF){
			cout << "disjoint" << endl;
		}
		else{
			printf("%d %d\n",maxn,max);
		}
	}	
	return 0;
}

POJ 1125 Stockbroker Grapevine Floyd 最短路

标签：图   poj   

原文地址：http://blog.csdn.net/qq_24667639/article/details/45501303