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Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
/* if(head==null) return false;
ListNode fast=head;
ListNode slow=head;
while(fast!=null){
slow=slow.next;
if(fast.next!=null){
fast=fast.next.next;
}else {
return false;
}
if(slow==fast) return true;
}
return false;*/
ListNode fast=head;
ListNode slow=head;
while(fast!=null&&fast.next!=null){
slow=slow.next;
fast=fast.next.next;
if(slow==fast)break;
}
if(fast==null||fast.next==null){
return false;
}
return true;
}
}
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原文地址:http://www.cnblogs.com/qiaomu/p/4479058.html