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leetcode_191题——Number of 1 Bits(外运算)

时间:2015-05-05 21:14:37      阅读:124      评论:0      收藏:0      [点我收藏+]

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Number of 1 Bits

 Total Accepted: 25965 Total Submissions: 70075My Submissions

 

Write a function that takes an unsigned integer and returns the number of ’1‘ bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11‘ has binary representation 00000000000000000000000000001011, so the function should return 3.

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

 

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     这道题考虑按位与运算和位的左移右移就可以了

#include<iostream>
#include<bitset>
typedef unsigned int uint32_t;

using namespace std;

int hammingWeight(uint32_t n)
{
	unsigned int temp=1;
	int result=0;
	for(int i=0;i<32;i++)
	{
		int temp2=temp<<i;
		if((n&temp2)!=0)
			result+=1;
	}
	return result;
}

int main()
{
	cout<<hammingWeight(11)<<endl;

}

  

leetcode_191题——Number of 1 Bits(外运算)

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原文地址:http://www.cnblogs.com/yanliang12138/p/4480087.html

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