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【题目】
Find the contiguous subarray within an array (containing at least one number) which has the largest product.
For example, given the array [2,3,-2,4]
,
the contiguous subarray [2,3]
has the largest product = 6
.
【analyze】
1.动态规划的算法,与Maximum Subarray类似
2.不过需要考虑两个负数相乘又会成为正数
3.设置局部最大值(正),局部最小值(负)和全局最大值
【算法】
public class Solution { public int maxProduct(int[] nums) { if(nums==null||nums.length==0) return 0; if(nums.length==1) return nums[0]; int local_max=nums[0]; int local_min=nums[0]; int global=nums[0]; for(int i=1;i<nums.length;i++) { int temp=local_max; local_max=Math.max(Math.max(nums[i]*local_max,nums[i]),nums[i]*local_min); //local_max*nums[i],num[i]和num[i]*local_min的比较 local_min=Math.min(Math.min(nums[i]*local_min,nums[i]),nums[i]*temp); global=Math.max(local_max,global); } return global; } }
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原文地址:http://www.cnblogs.com/hwu2014/p/4480226.html