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【题目链接:HDOJ-2952】
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2476 Accepted Submission(s): 1621
1 #include<iostream> 2 #include<cstring> 3 using namespace std; 4 const int MAXN = 105; 5 int Map[MAXN][MAXN] = {0}; 6 int vis[MAXN][MAXN] = {0}; 7 int dfs(int a,int b){ 8 if(Map[a][b] == 0 || vis[a][b] == 1) return 0; 9 vis[a][b] = 1; 10 //环顾四周 11 dfs(a - 1,b); //下 12 dfs(a + 1,b); //上 13 dfs(a,b - 1); //左 14 dfs(a,b + 1); //右 15 return 0; 16 } 17 int main(){ 18 int n; 19 cin >> n; 20 while(n--){ 21 int a,b,i,j,sum = 0; 22 memset(Map,0,sizeof(Map)); 23 memset(vis,0,sizeof(vis)); 24 cin >> a >> b; 25 for(i = 0;i < a;i++){ 26 for(j = 0;j < b;j++){ 27 char ac; 28 cin >> ac; 29 if(ac == ‘#‘) 30 Map[i][j] = 1; 31 else Map[i][j] = 0; 32 } 33 } 34 for(i = 0;i < a;i++) 35 for(j = 0;j < b;j++){ 36 if(Map[i][j] == 0 || vis[i][j] == 1) 37 continue; 38 else{ 39 40 dfs(i,j); 41 sum++; 42 } 43 } 44 cout << sum << endl; 45 } 46 return 0; 47 }
【题目链接:NYOJ-27】
可以说两题完全相似。
1 2 #include<iostream> 3 #include<cstring> 4 using namespace std; 5 const int MAXN = 105; 6 int Map[MAXN][MAXN] = {0}; 7 int vis[MAXN][MAXN] = {0}; 8 int dfs(int a,int b){ 9 if(Map[a][b] == 0 || vis[a][b] == 1) return 0; 10 vis[a][b] = 1; 11 //环顾四周 12 dfs(a - 1,b); //下 13 dfs(a + 1,b); //上 14 dfs(a,b - 1); //左 15 dfs(a,b + 1); //右 16 return 0; 17 } 18 int main(){ 19 int n; 20 cin >> n; 21 while(n--){ 22 int a,b,i,j,sum = 0; 23 memset(Map,0,sizeof(Map)); 24 memset(vis,0,sizeof(vis)); 25 cin >> a >> b; 26 for(i = 1;i <= a;i++) 27 for(j = 1;j <= b;j++){ 28 cin >> Map[i][j]; 29 } 30 for(i = 1;i <= a;i++) 31 for(j = 1;j <= b;j++){ 32 if(Map[i][j] == 0 || vis[i][j] == 1) 33 continue; 34 else{ 35 sum++; 36 dfs(i,j); 37 } 38 } 39 cout << sum << endl; 40 } 41 return 0; 42 }
【DFS深搜初步】HDOJ-2952 Counting Sheep、NYOJ-27 水池数目
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原文地址:http://www.cnblogs.com/zhengbin/p/4482992.html