码迷,mamicode.com
首页 > 其他好文 > 详细

Leetcode23: Count and Say

时间:2015-05-07 10:27:50      阅读:85      评论:0      收藏:0      [点我收藏+]

标签:algorithm   leetcode   

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

class Solution {
public:
    string countSay(string &str)
    {
        str.append("0");
        stringstream ss;
        int count = 0;
        char temp = str[0];
        for(int i = 0; i < str.size(); i++)
        {
            if(str[i] == temp)
                count++;
            else
            {
                ss << count << temp;
                count = 1;
                temp = str[i];
            }
        }
        return ss.str();
    }
    string countAndSay(int n) {
        string str = "1";
        for(int i = 1; i < n; i++)
        {
            str = countSay(str);
        }
        return str;
    }
};
之所以末尾追加一个0,是为了防止当前字符串的末尾是连续的n个相同的数,导致判断到末尾时依旧执行count++但是不写入stream流里。
技术分享

Leetcode23: Count and Say

标签:algorithm   leetcode   

原文地址:http://blog.csdn.net/u013089961/article/details/45556623

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!