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https://leetcode.com/problems/single-number-ii/
https://leetcode.com/discuss/6632/challenge-me-thx
Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
1 public class Solution { 2 public static int singleNumber(int[] nums) { 3 int len=nums.length; 4 int one=0;int two=0; 5 for(int i=0;i<len;i++){ 6 one=(one^nums[i])&~two; 7 two=(two^nums[i])&~one; 8 } 9 return one; 10 } 11 public static void main(String[]args){ 12 int[]nums={1,1,1,2,3,3,3}; 13 System.out.println(singleNumber(nums)); 14 } 15 }
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原文地址:http://www.cnblogs.com/qq1029579233/p/4484216.html