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The Lead Game Add problem to Todo list Problem code: TLG

时间:2015-05-07 14:17:40      阅读:97      评论:0      收藏:0      [点我收藏+]

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 1 ‘‘‘def count_lead(first, second):
 2     if first > second:
 3         return 1, first - second
 4     elif first == second: # 题目中没有说明相等的情况
 5         return 0, 0
 6     else:
 7         return 2, second - first‘‘‘ 
 8 
 9 
10 def main():
11     n = int(raw_input())
12     lead = 0
13     winner = 0 # 有些初始值不放置,判断不成立而输出时,为空了就
14     num1 = 0
15     num2 = 0
16     while n > 0:
17         first, second = map(int, raw_input().split())
18         if abs(first-second) > lead: # 绝对值函数
19             lead = abs(first-second)
20         num1 += first
21         num2 += second
22         n -= 1
23 
24     print num1, num2
25     if num1 > num2: # 这个地方题目有歧义,总分赢还是分局赢
26         winner = 1
27     else:
28         winner = 2
29 
30     print "%d %d" % (winner, lead) # 注意满足题目输出的的格式要求,int整数
31 
32 main()

http://www.codechef.com/problems/TLG

 

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The Lead Game Add problem to Todo list Problem code: TLG

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原文地址:http://www.cnblogs.com/sangocare/p/4484547.html

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