Remove Duplicates from Sorted List
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
解题思路:
链表的一般技巧就是增加一个伪头结点,然后在返回的时候删除伪头结点即可,这样就能减少不同情况的讨论。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
ListNode* myHead=new ListNode(0);
myHead->next = head;
ListNode *p=myHead, *q;
while(p->next!=NULL&&p->next->next!=NULL){
if(p->next->val == p->next->next->val){
q=p->next;
p->next = p->next->next;
delete q;
}else{
p=p->next;
}
}
p=myHead;
myHead=myHead->next;
delete p;
return myHead;
}
};[LeetCode] Remove Duplicates from Sorted List
原文地址:http://blog.csdn.net/kangrydotnet/article/details/45560675