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leetcode--Merge Intervals

时间:2014-06-13 15:12:35      阅读:180      评论:0      收藏:0      [点我收藏+]

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Given a collection of intervals, merge all overlapping intervals.

For example,
Given [1,3],[2,6],[8,10],[15,18],
return [1,6],[8,10],[15,18].

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public class Solution {
    /**There is not special algorithm for this problem.<br>
     * 1. sort the intervals according to the start point
     * 2. linear scan the sorted intervals and then merge them together
     *
     * @param intervals --List of Intervals.
     * @return --List of Intervals, in which no intervals have overlaps
     * @author Averill Zheng
     * @version 2014-06-12--world cup opening day
     * @since JDK 1.7
     */
    public List<Interval> merge(List<Interval> intervals) {
        List<Interval> result = new ArrayList<Interval>();
        if(!intervals.isEmpty()){
            Collections.sort(intervals, new IntervalComparator());
            int length = intervals.size();
            int start = intervals.get(0).start;
            int end = intervals.get(0).end;
            for(int i = 1; i < length; ++i){
                Interval current = intervals.get(i);
                if(current.start <= end)
                    end = Math.max(end, current.end);
                else{
                    result.add(new Interval(start, end));
                    start = current.start;
                    end = current.end;
                }
            }
            result.add(new Interval(start, end));
        }
        return result;
    }
}
 
class IntervalComparator implements Comparator<Interval>{
    public int compare(Interval a, Interval b){
        return Integer.compare(a.start, b.start);
    }
}

  

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leetcode--Merge Intervals

标签:class   blog   code   java   tar   com   

原文地址:http://www.cnblogs.com/averillzheng/p/3785015.html

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