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Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2624 Accepted Submission(s): 1178
#include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<algorithm> #include<cstdlib> #include<vector> using namespace std; vector<int> e[100005]; int n,m,dist[100005],k; void dfs(int u,int father) { for(int i=0;i<e[u].size();i++) { int v=e[u][i]; if(v==father) continue; dist[v]=dist[u]+1; dfs(v,u); } } int main() { int tt; scanf("%d",&tt); while(tt--) { scanf("%d%d",&n,&m); for(int i=1;i<=n;i++) e[i].clear(); for(int i=1;i<n;i++) { int x,y; scanf("%d%d",&x,&y); e[x].push_back(y); e[y].push_back(x); } memset(dist,0,sizeof(dist)); dfs(1,-1); int len=0,u; for(int i=1;i<=n;i++) { if(dist[i]>len) { len=dist[i]; u=i; } } memset(dist,0,sizeof(dist)); dfs(u,-1); len=0; for(int i=1;i<=n;i++) { if(dist[i]>len) len=dist[i]; } len++; while(m--) { scanf("%d",&k); if(len>=k) { printf("%d\n",k-1); } else { printf("%d\n",(k-len)*2+len-1); } } } return 0; }
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原文地址:http://www.cnblogs.com/water-full/p/4493956.html