标签:style class blog code color 2014
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Follow up:
Could you do this in-place?
思路:第一种思路是一层一层的进行旋转,比较直观;第二种思路则比较取巧,首先沿着副对角线翻转一次,然后沿着水平中线翻转一次。
代码一:
class Solution { public: void rotate(vector<vector<int> > &matrix) { int n = matrix.size(); for(int i = 0; i < n / 2; i++) for(int j = i; j < n - i - 1;j++) { int temp = matrix[i][j]; matrix[i][j] = matrix[n - 1 - j][i]; matrix[n - 1 - j][i] = matrix[n - 1 - i][n - 1 - j]; matrix[n - 1 - i][n - 1 - j] = matrix[j][n - 1 - i]; matrix[j][n - 1 - i] = temp; } } };
// LeetCode, Rotate Image // 思路1,时间复杂度O(n^2),空间复杂度O(1) class Solution { public: void rotate(vector<vector<int>>& matrix) { const int n = matrix.size(); for (int i = 0; i < n; ++i) // 沿着副对角线反转 for (int j = 0; j < n - i; ++j) swap(matrix[i][j], matrix[n - 1 - j][n - 1 - i]); for (int i = 0; i < n / 2; ++i) // 沿着水平中线反转 for (int j = 0; j < n; ++j) swap(matrix[i][j], matrix[n - 1 - i][j]); } };
【Leetcode】Rotate Image,布布扣,bubuko.com
标签:style class blog code color 2014
原文地址:http://blog.csdn.net/lipantechblog/article/details/30474613