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Input
1 #include<iostream>/*打表找规律*/ 2 using namespace std; 3 int main(){ 4 int n; 5 while(cin>>n){ 6 if(n%4==2) cout<<"yes"<<endl; 7 else cout<<"no"<<endl; 8 }return 0; 9 }
1021 Fibonacci Again (hdoj)
原文地址:http://www.cnblogs.com/a1225234/p/4496184.html