标签:sorted
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
The number of elements initialized in nums1
将两个数组合并到其中一个数组中,从后往前遍历。
将两个数组合并到另一个缓存数组中,一般从前向后遍历
//时间复杂度O(m+n), 空间复杂度O(1)
void merge(int* nums1, int m, int* nums2, int n) {
int i = m-1, j = n-1, k = m+n-1;
while (j >= 0) {
if (i >= 0)
nums1[k--] = (nums1[i] > nums2[j]) ? nums1[i--] : nums2[j--];
else
nums1[k--] = nums2[j--];
}
return;
}
标签:sorted
原文地址:http://blog.csdn.net/quzhongxin/article/details/45690033