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| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 9965 | Accepted: 4087 |
Description

Input
Output
Sample Input
1 7 2 6 1 2 1 4 4 5 3 7 3 1
Sample Output
1 2
Source
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdlib>
#include<string>
#include<vector>
#define INF 100000000
using namespace std;
vector<int> e[20005];
int n,dp[20005],ans,num;
void dfs(int u,int father)
{
int maxx=0;
dp[u]=1;
for(int i=0;i<e[u].size();i++)
{
int v=e[u][i];
if(v==father)
continue;
dfs(v,u);
dp[u]+=dp[v];
maxx=max(maxx,dp[v]);
}
maxx=max(maxx,n-dp[u]);
if(maxx==ans)
{
if(u<num)
num=u;
}
if(maxx<ans)
{
ans=maxx;
num=u;
}
}
int main()
{
int tt;
scanf("%d",&tt);
while(tt--)
{
scanf("%d",&n);
for(int i=1;i<=n;i++)
e[i].clear();
num=1;
ans=INF;
for(int i=1;i<n;i++)
{
int x,y;
scanf("%d%d",&x,&y);
e[x].push_back(y);
e[y].push_back(x);
}
dfs(1,-1);
printf("%d %d\n",num,ans);
}
return 0;
}
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原文地址:http://www.cnblogs.com/water-full/p/4501674.html