树的子结构

标签：c++   刷题   

struct BinaryTreeNode{
	int m_nValue;
	BinaryTreeNode *m_pLeft;
	BinaryTreeNode *m_pRight;
};

//在数A中查找与树B根结点值相同的结点，然后递归判断，查找过程也是递归
bool HasSubTree(BinaryTreeNode *pRoot1, BinaryTreeNode *pRoot2)
{
	bool result=false;
	if (pRoot1->m_nValue==pRoot2->m_nValue)
	{
		result=DoesTree1HaveTree2(pRoot1,pRoot2);
		if (!result)
		{
			result=HasSubTree(pRoot1->m_pLeft,pRoot2);
		}
		if (!result)
		{
			result=HasSubTree(pRoot1->m_pRight,pRoot2);
		}
	}
	return result;
}

//判断树A的子树是不是和树B有相同的结构
bool DoesTree1HaveTree2(BinaryTreeNode *pRoot1, BinaryTreeNode *pRoot2)
{
	if (pRoot2==NULL)
	{
		return true;
	}
	if (pRoot1==NULL)
	{
		return false;
	}
	if (pRoot1->m_nValue!=pRoot2->m_nValue)
	{
		return false;
	}
	return DoesTree1HaveTree2(pRoot1->m_pLeft,pRoot2->m_pLeft)&&DoesTree1HaveTree2(pRoot1->m_pRight,
		pRoot2->m_pRight);
}

树的子结构

标签：c++   刷题   

原文地址：http://blog.csdn.net/lsh_2013/article/details/45750537