求三个数值的中间值的宏定义

标签：宏   c语言 嵌入式   算法   

怎么用一个宏来求三个数值的中间值呢？请看：

#include <stdio.h>

#define MIDDLE(x,y,z) ((x)<(y)?((y)<(z)?(y):(x)<(z)?(z):(x)):((y)>(z)?(y):(x)>(z)?(z):(x)))

int main(void)
{
    printf("MIDDLE(%d,%d,%d) = %d\r\n", 1,2,3,MIDDLE(1,2,3));
    printf("MIDDLE(%d,%d,%d) = %d\r\n", 2,1,3,MIDDLE(2,1,3));
    printf("MIDDLE(%d,%d,%d) = %d\r\n", 1,3,2,MIDDLE(1,3,2));
    printf("MIDDLE(%d,%d,%d) = %d\r\n", -1,-2,-3,MIDDLE(-1,-2,-3));
    printf("MIDDLE(%d,%d,%d) = %d\r\n", -2,-1,-3,MIDDLE(-2,-1,-3));
    printf("MIDDLE(%d,%d,%d) = %d\r\n", -1,-3,-2,MIDDLE(-1,-3,-2));
    printf("MIDDLE(%f,%f,%f) = %f\r\n", 1.1,2.4,3.5,MIDDLE(1.1,2.4,3.5));
    printf("MIDDLE(%f,%f,%f) = %f\r\n", 1.1,3.3,2.4,MIDDLE(1.1,3.3,2.4));
    printf("MIDDLE(%f,%f,%f) = %f\r\n", 2.4,1.1,3.3,MIDDLE(2.4,1.1,3.3));
    
    return 0;
}

可见结果均正确！

求三个数值的中间值的宏定义

标签：宏   c语言 嵌入式   算法   

原文地址：http://blog.csdn.net/dcx1205/article/details/45750305