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【leetcode】Count and Say

时间:2015-05-16 19:55:50      阅读:97      评论:0      收藏:0      [点我收藏+]

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The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.
Given an integer n, generate the n^th sequence.

Note: The sequence of integers will be represented as a string.

 

 1 class Solution {
 2 public:
 3     string count(const string &say)
 4     {
 5         stringstream ss;
 6         int count=0;
 7         char last=say[0];
 8 
 9         for(size_t i=0;i<=say.size();++i)
10         {
11             if(say[i]==last)
12             {
13                 ++count;
14             }else{
15                 ss<<count<<last;
16                 count=1;
17                 last=say[i];
18             }
19         }
20 
21         return ss.str();
22     }
23 
24 
25 
26     string countAndSay(int n) {
27         if(n==0) return string();
28 
29         string say="1";
30 
31         for(int i=1;i<n;i++)
32         {
33             say=count(say);
34         }
35 
36         return say;
37     }
38 };

 

【leetcode】Count and Say

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原文地址:http://www.cnblogs.com/jawiezhu/p/4508251.html

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