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【Validate Binary Search Tree】cpp

时间:2015-05-16 20:21:48      阅读:91      评论:0      收藏:0      [点我收藏+]

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题目:

Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

代码:

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isValidBST(TreeNode* root) {
            if (!root) return true;
            stack<TreeNode *> sta;
            vector<int> traversal;
            TreeNode *p = root;
            while ( !sta.empty() || p )
            {
                if (p){
                    sta.push(p);
                    p = p->left;
                }
                else{
                    p = sta.top();
                    sta.pop();
                    if ( !traversal.empty() && traversal[traversal.size()-1]>=p->val ) return false;
                    traversal.push_back(p->val);
                    p = p->right;
                }
            }
            return true;
    }
};

tips:

中序遍历BST;并保留每次访问的元素;如果中序遍历的前一个元素不小于后一个元素,则返回false;全部遍历过后无问题,则返回true。

题目中有一个test case是:[-2147483648],即INT_MIN。由于有这个非常极端的case存在,之前那种设一个pre = INT_MIN的办法就行不通了,暂时老老实实用一个vector来代替。

【Validate Binary Search Tree】cpp

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原文地址:http://www.cnblogs.com/xbf9xbf/p/4508313.html

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