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[csu/coj 1083]贪心

时间:2015-05-17 07:06:41      阅读:158      评论:0      收藏:0      [点我收藏+]

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题意:给定n个线段,问能不能把x,y,z个长度为1,2,3的线段不重合地放进去。

思路:首先如果n个线段长度比要放的长度之和小,则无解,否则先考虑放2和3,如果2和3放下了1肯定可以放下(这是显然的)。于是我们贪心先把n个线段放满长度为3的线段,然后再考虑删去长度为3的线段来放长度为2的线段,删的时候要选择删去以后空闲的线段长度最多的删,比如某个线段本身有1的空闲线段,这时如果删去一条放在上面的长度为3的线段,则空闲线段变为4,这种情况优先删,其它情况次之。实现上采用优先队列,保存每个线段的长度为3的线段个数和空闲线段长度(只有0和1两种可能),然后按照前面说的优先级重载小于号就ok了,非常方便。

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  1 #pragma comment(linker, "/STACK:10240000,10240000")
  2 
  3 #include <iostream>
  4 #include <cstdio>
  5 #include <algorithm>
  6 #include <cstdlib>
  7 #include <cstring>
  8 #include <map>
  9 #include <queue>
 10 #include <deque>
 11 #include <cmath>
 12 #include <vector>
 13 #include <ctime>
 14 #include <cctype>
 15 #include <stack>
 16 #include <set>
 17 #include <bitset>
 18 #include <functional>
 19 #include <numeric>
 20 #include <stdexcept>
 21 #include <utility>
 22 
 23 using namespace std;
 24 
 25 #define mem0(a) memset(a, 0, sizeof(a))
 26 #define mem_1(a) memset(a, -1, sizeof(a))
 27 #define lson l, m, rt << 1
 28 #define rson m + 1, r, rt << 1 | 1
 29 #define define_m int m = (l + r) >> 1
 30 #define rep_up0(a, b) for (int a = 0; a < (b); a++)
 31 #define rep_up1(a, b) for (int a = 1; a <= (b); a++)
 32 #define rep_down0(a, b) for (int a = b - 1; a >= 0; a--)
 33 #define rep_down1(a, b) for (int a = b; a > 0; a--)
 34 #define all(a) (a).begin(), (a).end()
 35 #define lowbit(x) ((x) & (-(x)))
 36 #define constructInt4(name, a, b, c, d) name(int a = 0, int b = 0, int c = 0, int d = 0): a(a), b(b), c(c), d(d) {}
 37 #define constructInt3(name, a, b, c) name(int a = 0, int b = 0, int c = 0): a(a), b(b), c(c) {}
 38 #define constructInt2(name, a, b) name(int a = 0, int b = 0): a(a), b(b) {}
 39 #define pchr(a) putchar(a)
 40 #define pstr(a) printf("%s", a)
 41 #define sstr(a) scanf("%s", a)
 42 #define sint(a) scanf("%d", &a)
 43 #define sint2(a, b) scanf("%d%d", &a, &b)
 44 #define sint3(a, b, c) scanf("%d%d%d", &a, &b, &c)
 45 #define pint(a) printf("%d\n", a)
 46 #define test_print1(a) cout << "var1 = " << a << endl
 47 #define test_print2(a, b) cout << "var1 = " << a << ", var2 = " << b << endl
 48 #define test_print3(a, b, c) cout << "var1 = " << a << ", var2 = " << b << ", var3 = " << c << endl
 49 #define mp(a, b) make_pair(a, b)
 50 #define pb(a) push_back(a)
 51 
 52 typedef long long LL;
 53 typedef pair<int, int> pii;
 54 typedef vector<int> vi;
 55 
 56 const int dx[8] = {0, 0, -1, 1, 1, 1, -1, -1};
 57 const int dy[8] = {-1, 1, 0, 0, 1, -1, 1, -1 };
 58 const int maxn = 4e5 + 7;
 59 const int md = 1e9 + 7;
 60 const int inf = 1e9 + 7;
 61 const LL inf_L = 1e18 + 7;
 62 const double pi = acos(-1.0);
 63 const double eps = 1e-6;
 64 
 65 template<class T>T gcd(T a, T b){return b==0?a:gcd(b,a%b);}
 66 template<class T>bool max_update(T &a,const T &b){if(b>a){a = b; return true;}return false;}
 67 template<class T>bool min_update(T &a,const T &b){if(b<a){a = b; return true;}return false;}
 68 template<class T>T condition(bool f, T a, T b){return f?a:b;}
 69 template<class T>void copy_arr(T a[], T b[], int n){rep_up0(i,n)a[i]=b[i];}
 70 int make_id(int x, int y, int n) { return x * n + y; }
 71 
 72 struct Node {
 73     int cnt3, rest;
 74     bool operator < (const Node &that) const {
 75         return that.rest && that.cnt3 || that.cnt3 > cnt3 && !(rest && cnt3);
 76     }
 77     constructInt2(Node, cnt3, rest);
 78 };
 79 
 80 pii node[maxn];
 81 int a[maxn], tot, s, t, x, y, z, m;
 82 int Left[maxn], Right[maxn];
 83 int main() {
 84     //freopen("in.txt", "r", stdin);
 85     while (cin >> s >> t) {
 86         cin >> x >> y >> z;
 87         cin >> m;
 88         rep_up0(i, m) {
 89             sint2(node[i].first, node[i].second);
 90         }
 91         sort(node, node + m);
 92         tot = 0;
 93         int R = -1;
 94         int cs = 0;
 95         rep_up0(i, m) {
 96             if (node[i].first - R > 1) {
 97                 Left[cs] = R + 1;
 98                 Right[cs ++] = node[i].first - 1;
 99             }
100             max_update(R, node[i].second);
101         }
102         if (R < 1e9) {
103             Left[cs] = R + 1;
104             Right[cs ++] = 1e9;
105         }
106         rep_up0(i, cs) {
107             int L = max(s, Left[i]), R = min(t, Right[i]);
108             if (R >= L) a[tot ++] = R - L + 1;
109         }
110         sort(a, a + tot);
111         //rep_up0(i, tot) cout << a[i] << " ";
112         int sum = 0;
113         rep_up0(i, tot) sum += a[i];
114         if (sum < x + 2 * y + 3 * z) {
115             puts("NO");
116             continue;
117         }
118         priority_queue<Node> Q;
119         int cnt2 = 0;
120         rep_up0(i, tot) {
121             Q.push(Node(a[i] / 3, a[i] % 3 % 2));
122             cnt2 += a[i] % 3 / 2;
123         }
124 
125         while (!Q.empty()) {
126             if (cnt2 >= y) break;
127             Node Hnode = Q.top(); Q.pop();
128             if (Hnode.rest) {
129                 if (Hnode.cnt3) {
130                     cnt2 += 2;
131                     Q.push(Node(Hnode.cnt3 - 1, 0));
132                 }
133             }
134             else {
135                 if (Hnode.cnt3) {
136                     cnt2 ++;
137                     Q.push(Node(Hnode.cnt3 - 1, 1));
138                 }
139             }
140         }
141 
142         int cnt3 = 0;
143         while (!Q.empty()) {
144             Node Hnode = Q.top(); Q.pop();
145             cnt3 += Hnode.cnt3;
146         }
147 
148         puts(cnt2 >= y && cnt3 >= z? "YES" : "NO") ;
149     }
150     return 0;
151 }
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[csu/coj 1083]贪心

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原文地址:http://www.cnblogs.com/jklongint/p/4509081.html

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