
标签:csu


![]()
abcbcbcbca
abbbcdcdcdabbbcdcdcd
0
Case 1: 7
Case 2: 11
<pre name="code" class="cpp">#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <math.h>
#include <bitset>
#include <algorithm>
#include <climits>
using namespace std;
#define LS 2*i
#define RS 2*i+1
#define UP(i,x,y) for(i=x;i<=y;i++)
#define DOWN(i,x,y) for(i=x;i>=y;i--)
#define MEM(a,x) memset(a,x,sizeof(a))
#define W(a) while(a)
#define LL long long
#define N 505
#define MOD 19999997
#define INF 0x3f3f3f3f
#define EXP 1e-8
int dp[N][N],next1[N],cas = 1;
char s[N];
int kmp(char *s,int len)//kmp求循环节的长度
{
next1[0] = next1[1] = 0;
int i;
UP(i,1,len-1)
{
int j = next1[i];
W((j&&s[i]!=s[j]))
{
j = next1[j];
}
if(s[i]==s[j])
next1[i+1]=j+1;
else
next1[i+1]=0;
}
return len-next1[len];
}
int getbit(int x)
{
int cnt = 0;
W(x)
{
x/=10;
cnt++;
}
return cnt;
}
void DP()
{
int n = strlen(s+1);
int len,l,r,k,i;
UP(i,1,n)
dp[i][i]=1;
UP(len,2,n)//区间dp求解最优值
{
for(l = 1; l+len-1<=n; l++)
{
r = l+len-1;
dp[l][r]=dp[l][l]+dp[l+1][r];
UP(k,l+1,r-1)
{
dp[l][r]=min(dp[l][r],dp[l][k]+dp[k+1][r]);
}
int t = kmp(s+l,len);
if(len%t==0)//现在枚举的串是一个周期循环
{
int tem = dp[l][l+t-1];
if(t>1) tem+=2;//因为不是一个字符的话要加括号
tem+=getbit(len/t);//周期数
dp[l][r]=min(tem,dp[l][r]);
}
}
}
printf("Case %d: %d\n",cas++,dp[1][n]);
}
int main()
{
W(~scanf("%s",s+1))
{
if(s[1]=='0')
break;
DP();
}
return 0;
}CSU1620: A Cure for the Common Code(KMP+区间DP)
标签:csu
原文地址:http://blog.csdn.net/libin56842/article/details/45794061