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private long exitTime = 0;
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK
&& event.getAction() == KeyEvent.ACTION_DOWN) {
if ((System.currentTimeMillis() - exitTime) > 2000) {
Toast.makeText(getApplicationContext(), "再按一次退出程序",
Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
} else {
moveTaskToBack(false);
finish();
}
return true;
}
return super.onKeyDown(keyCode, event);
}
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原文地址:http://www.cnblogs.com/wandering-soul/p/4511555.html