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Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
注意事项：while停止的条件要特备注意；各种输入情况都要考虑到；如果首节点就是要删除的节点肿么办，等等问题。
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode removeElements(ListNode head, int val) { if(head == null) return null; if(head.next==null && head.val==val) return null; if(head.next==null && head.val!=val) return head; ListNode p = head; while(head.next!=null && head.val==val){ p = head; head = head.next; p.next = null; } p = head; ListNode q = p.next; while(p.next!=null){ q = p.next; if(q.val == val){ p.next = q.next; q.next = null; } else{ p = q; q = p.next; } } if(head.val==val)//做最后的检查，看是否首节点是要删除的元素 return null; return head; } }
LeetCode--Remove Linked List Element
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原文地址：http://www.cnblogs.com/little-YTMM/p/4511473.html
