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以前写的1061但一直没懂,后来懂了但忘写解题报告了

做了1283顺便补一下吧

1061 我是orz https://www.byvoid.com/blog/noi-2008-employee/#more-916

这类类似线性规划的费用流构造,大概有这么几个步骤

首先找出不等式约束关系,然后添加辅助变量变成等式,并写出目标函数

然后通过做差构造,使每个变量都出现在两个等式中

每个等式整理成变量+常量=0 根据入流=出硫,我们把每个等式作为一个点

如果我们把等式左边系数为正作为入流,系数为负作为出流

则,对于每个变量,如果在等式j出现时系数为正,等式k系数为-,则k向j连边 流量为无穷,费用由目标函数决定

如果是常量,正则源点向这个等式连边,负则其向汇点连边,流量为常量的绝对值

然后我们就可以跑费用流了

技术分享
  1 const inf=2147483647;
  2 
  3 type node=record
  4        next,point,flow:longint;
  5        cost:int64;
  6      end;
  7 
  8 var edge:array[0..1000010] of node;
  9     c,p,cur,pre:array[0..1010] of longint;
 10     d:array[0..1010] of int64;
 11     v:array[0..1010] of boolean;
 12     q:array[0..1000010] of longint;
 13     b,e,w,i,j,n,m,len,t:longint;
 14     ans:int64;
 15 
 16 procedure add(x,y,f:longint;w:int64);
 17   begin
 18     inc(len);
 19     edge[len].point:=y;
 20     edge[len].flow:=f;
 21     edge[len].cost:=w;
 22     edge[len].next:=p[x];
 23     p[x]:=len;
 24   end;
 25 
 26 function spfa:boolean;
 27   var  f,r,x,y,i:longint;
 28   begin
 29     f:=1;
 30     r:=1;
 31     q[1]:=0;
 32     for i:=1 to t do
 33       d[i]:=inf;
 34     fillchar(v,sizeof(v),false);
 35     v[0]:=true;
 36     while f<=r do
 37     begin
 38       x:=q[f];
 39       v[x]:=false;
 40       i:=p[x];
 41       while i<>-1 do
 42       begin
 43         y:=edge[i].point;
 44         if edge[i].flow>0 then
 45           if d[y]>d[x]+edge[i].cost then
 46           begin
 47             d[y]:=d[x]+edge[i].cost;
 48             pre[y]:=x;
 49             cur[y]:=i;
 50             if not v[y] then
 51             begin
 52               inc(r);
 53               q[r]:=y;
 54               v[y]:=true;
 55             end;
 56           end;
 57         i:=edge[i].next;
 58       end;
 59       inc(f);
 60     end;
 61     if d[t]=inf then exit(false) else exit(true);
 62   end;
 63 
 64 procedure mincost;
 65   var i,j:longint;
 66       neck:int64;
 67   begin
 68     while spfa do
 69     begin
 70       neck:=inf;
 71       i:=t;
 72       while i<>0 do
 73       begin
 74         j:=cur[i];
 75         if edge[j].flow<neck then neck:=edge[j].flow;
 76         i:=pre[i];
 77       end;
 78       i:=t;
 79       while i<>0 do
 80       begin
 81         j:=cur[i];
 82         dec(edge[j].flow,neck);
 83         inc(edge[j xor 1].flow,neck);
 84         i:=pre[i];
 85       end;
 86       ans:=ans+d[t]*neck;
 87     end;
 88   end;
 89 
 90 begin
 91   readln(n,m);
 92   len:=-1;
 93   fillchar(p,sizeof(p),255);
 94   t:=n+2;
 95   for i:=1 to n do
 96     read(c[i]);
 97   for i:=1 to m do
 98   begin
 99     readln(b,e,w);
100     add(b,e+1,inf,w);
101     add(e+1,b,0,-w);
102   end;
103   for i:=1 to n+1 do
104   begin
105     w:=c[i]-c[i-1];
106     if w>=0 then
107     begin
108       add(0,i,w,0);
109       add(i,0,-w,0);
110     end
111     else begin
112       add(i,t,-w,0);
113       add(t,i,0,0);
114     end;
115     if i>1 then
116     begin
117       add(i,i-1,inf,0);
118       add(i-1,i,0,0);
119     end;
120   end;
121   mincost;
122   writeln(ans);
123 end.
1061
技术分享
 1 type node=record
 2        po,next,flow,cost:longint;
 3      end;
 4 
 5 var e:array[0..800010] of node;
 6     d,pre,cur,p:array[0..1010] of longint;
 7     v:array[0..1010] of boolean;
 8     q:array[0..1000010] of longint;
 9     i,x,y,n,m,len,t,k:longint;
10 
11 procedure add(x,y,f,c:longint);
12   begin
13     inc(len);
14     e[len].po:=y;
15     e[len].flow:=f;
16     e[len].cost:=c;
17     e[len].next:=p[x];
18     p[x]:=len;
19   end;
20 
21 procedure build(x,y,f,c:longint);
22   begin
23     add(x,y,f,c);
24     add(y,x,0,-c);
25   end;
26 
27 function spfa:boolean;
28   var i,f,r,x,y:longint;
29   begin
30     fillchar(v,sizeof(v),false);
31     for i:=1 to t do
32       d[i]:=-1000000007;
33     d[0]:=0;
34     f:=1;
35     r:=1;
36     q[1]:=0;
37     while f<=r do
38     begin
39       x:=q[f];
40       v[x]:=false;
41       i:=p[x];
42       while i<>-1 do
43       begin
44         y:=e[i].po;
45         if e[i].flow>0 then
46           if d[y]<d[x]+e[i].cost then
47           begin
48             d[y]:=d[x]+e[i].cost;
49             pre[y]:=x;
50             cur[y]:=i;
51             if not v[y] then
52             begin
53               inc(r);
54               q[r]:=y;
55               v[y]:=true;
56             end;
57           end;
58         i:=e[i].next;
59       end;
60       inc(f);
61     end;
62     if d[t]<=0 then exit(false) else exit(true);
63   end;
64 
65 function maxcost:longint;
66   var i,j:longint;
67   begin
68     maxcost:=0;
69     while spfa do
70     begin
71       i:=t;
72       while i<>0 do
73       begin
74         j:=cur[i];
75         dec(e[j].flow);
76         inc(e[j xor 1].flow);
77         i:=pre[i];
78       end;
79       maxcost:=maxcost+d[t];
80     end;
81   end;
82 
83 begin
84   readln(n,m,k);
85   len:=-1;
86   fillchar(p,sizeof(p),255);
87   t:=n+1;
88   for i:=1 to n do
89   begin
90     read(x);
91     y:=i+m;
92     if y>n then y:=t;
93     build(i,y,1,x);
94     build(i,i+1,k,0);
95   end;
96   build(0,1,k,0);
97   writeln(maxcost);
98 end.
1283

 

bzoj1061 1283

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原文地址:http://www.cnblogs.com/phile/p/4511785.html

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